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0=-0.8x^2+7x-15
We move all terms to the left:
0-(-0.8x^2+7x-15)=0
We add all the numbers together, and all the variables
-(-0.8x^2+7x-15)=0
We get rid of parentheses
0.8x^2-7x+15=0
a = 0.8; b = -7; c = +15;
Δ = b2-4ac
Δ = -72-4·0.8·15
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*0.8}=\frac{6}{1.6} =3+1/1.3333333333333 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*0.8}=\frac{8}{1.6} =5 $
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